Base | Representation |
---|---|
bin | 11110000011111100111110… |
… | …110111100101001001001111 |
3 | 122100010102221121002100122101 |
4 | 132003330332313211021033 |
5 | 114312134242423431343 |
6 | 1145105455012055531 |
7 | 36564035132120305 |
oct | 3603747667451117 |
9 | 570112847070571 |
10 | 132213033030223 |
11 | 391442613a4772 |
12 | 129b39313045a7 |
13 | 58a0835303712 |
14 | 2491205a16275 |
15 | 104426ecc3e4d |
hex | 783f3ede524f |
132213033030223 has 4 divisors (see below), whose sum is σ = 132213591804208. Its totient is φ = 132212474256240.
The previous prime is 132213033030203. The next prime is 132213033030259. The reversal of 132213033030223 is 322030330312231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132213033030223 - 29 = 132213033029711 is a prime.
It is a super-3 number, since 3×1322130330302233 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132213033030191 and 132213033030200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132213033030203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 279031923 + ... + 279505348.
It is an arithmetic number, because the mean of its divisors is an integer number (33053397951052).
Almost surely, 2132213033030223 is an apocalyptic number.
132213033030223 is a deficient number, since it is larger than the sum of its proper divisors (558773985).
132213033030223 is an equidigital number, since it uses as much as digits as its factorization.
132213033030223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 558773984.
The product of its (nonzero) digits is 11664, while the sum is 28.
Adding to 132213033030223 its reverse (322030330312231), we get a palindrome (454243363342454).
The spelling of 132213033030223 in words is "one hundred thirty-two trillion, two hundred thirteen billion, thirty-three million, thirty thousand, two hundred twenty-three".
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