Base | Representation |
---|---|
bin | 1100000001100101010000… |
… | …1101011001001001111111 |
3 | 1201210221112200010212002212 |
4 | 3000121110031121021333 |
5 | 3213104231431243033 |
6 | 44041442550011035 |
7 | 2533131454610654 |
oct | 300312415311177 |
9 | 51727480125085 |
10 | 13221322134143 |
11 | 4238149735962 |
12 | 159646a046a7b |
13 | 74b9c4569ac6 |
14 | 339cb5c31c2b |
15 | 17ddb498a748 |
hex | c065435927f |
13221322134143 has 2 divisors, whose sum is σ = 13221322134144. Its totient is φ = 13221322134142.
The previous prime is 13221322134107. The next prime is 13221322134203. The reversal of 13221322134143 is 34143122312231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13221322134143 - 224 = 13221305356927 is a prime.
It is a super-3 number, since 3×132213221341433 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13221322134443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610661067071 + 6610661067072.
It is an arithmetic number, because the mean of its divisors is an integer number (6610661067072).
Almost surely, 213221322134143 is an apocalyptic number.
13221322134143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13221322134143 is an equidigital number, since it uses as much as digits as its factorization.
13221322134143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20736, while the sum is 32.
Adding to 13221322134143 its reverse (34143122312231), we get a palindrome (47364444446374).
The spelling of 13221322134143 in words is "thirteen trillion, two hundred twenty-one billion, three hundred twenty-two million, one hundred thirty-four thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •