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13221332201335 = 522960719023089
BaseRepresentation
bin1100000001100101010011…
…0011110010111101110111
31201210221120101002022200211
43000121110303302331313
53213104242020420320
644041443545450251
72533131636310246
oct300312463627567
951727511068624
1013221332201335
114238154391555
1215964714a0987
1374b9c668311b
14339cb72d295d
1517ddb57c855a
hexc0654cf2f77

13221332201335 has 16 divisors (see below), whose sum is σ = 15961133433600. Its totient is φ = 10513528091136.

The previous prime is 13221332201323. The next prime is 13221332201369. The reversal of 13221332201335 is 53310223312231.

It is a cyclic number.

It is not a de Polignac number, because 13221332201335 - 25 = 13221332201303 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13221332201297 and 13221332201306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8816530 + ... + 10206559.

It is an arithmetic number, because the mean of its divisors is an integer number (997570839600).

Almost surely, 213221332201335 is an apocalyptic number.

13221332201335 is a deficient number, since it is larger than the sum of its proper divisors (2739801232265).

13221332201335 is a wasteful number, since it uses less digits than its factorization.

13221332201335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19023930.

The product of its (nonzero) digits is 19440, while the sum is 31.

Adding to 13221332201335 its reverse (53310223312231), we get a palindrome (66531555513566).

The spelling of 13221332201335 in words is "thirteen trillion, two hundred twenty-one billion, three hundred thirty-two million, two hundred one thousand, three hundred thirty-five".

Divisors: 1 5 229 607 1145 3035 139003 695015 19023089 95115445 4356287381 11547015023 21781436905 57735075115 2644266440267 13221332201335