Base | Representation |
---|---|
bin | 1100000001100101010011… |
… | …0011110010111101110111 |
3 | 1201210221120101002022200211 |
4 | 3000121110303302331313 |
5 | 3213104242020420320 |
6 | 44041443545450251 |
7 | 2533131636310246 |
oct | 300312463627567 |
9 | 51727511068624 |
10 | 13221332201335 |
11 | 4238154391555 |
12 | 15964714a0987 |
13 | 74b9c668311b |
14 | 339cb72d295d |
15 | 17ddb57c855a |
hex | c0654cf2f77 |
13221332201335 has 16 divisors (see below), whose sum is σ = 15961133433600. Its totient is φ = 10513528091136.
The previous prime is 13221332201323. The next prime is 13221332201369. The reversal of 13221332201335 is 53310223312231.
It is a cyclic number.
It is not a de Polignac number, because 13221332201335 - 25 = 13221332201303 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13221332201297 and 13221332201306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8816530 + ... + 10206559.
It is an arithmetic number, because the mean of its divisors is an integer number (997570839600).
Almost surely, 213221332201335 is an apocalyptic number.
13221332201335 is a deficient number, since it is larger than the sum of its proper divisors (2739801232265).
13221332201335 is a wasteful number, since it uses less digits than its factorization.
13221332201335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19023930.
The product of its (nonzero) digits is 19440, while the sum is 31.
Adding to 13221332201335 its reverse (53310223312231), we get a palindrome (66531555513566).
The spelling of 13221332201335 in words is "thirteen trillion, two hundred twenty-one billion, three hundred thirty-two million, two hundred one thousand, three hundred thirty-five".
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