Base | Representation |
---|---|
bin | 1100000001100101010011… |
… | …0011110010111110001011 |
3 | 1201210221120101002022201120 |
4 | 3000121110303302332023 |
5 | 3213104242020420410 |
6 | 44041443545450323 |
7 | 2533131636310305 |
oct | 300312463627613 |
9 | 51727511068646 |
10 | 13221332201355 |
11 | 4238154391573 |
12 | 15964714a09a3 |
13 | 74b9c6683135 |
14 | 339cb72d2975 |
15 | 17ddb57c8570 |
hex | c0654cf2f8b |
13221332201355 has 64 divisors (see below), whose sum is σ = 22607659491840. Its totient is φ = 6578959435776.
The previous prime is 13221332201323. The next prime is 13221332201369. The reversal of 13221332201355 is 55310223312231.
13221332201355 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13221332201355 - 25 = 13221332201323 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3748744 + ... + 6363626.
It is an arithmetic number, because the mean of its divisors is an integer number (353244679560).
Almost surely, 213221332201355 is an apocalyptic number.
13221332201355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13221332201355 is a deficient number, since it is larger than the sum of its proper divisors (9386327290485).
13221332201355 is a wasteful number, since it uses less digits than its factorization.
13221332201355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2615180.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 13221332201355 its reverse (55310223312231), we get a palindrome (68531555513586).
The spelling of 13221332201355 in words is "thirteen trillion, two hundred twenty-one billion, three hundred thirty-two million, two hundred one thousand, three hundred fifty-five".
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