Base | Representation |
---|---|
bin | 11110000011111110010110… |
… | …111101110011010101010010 |
3 | 122100010120202121020212010121 |
4 | 132003332112331303111102 |
5 | 114312200304312244320 |
6 | 1145110301411220454 |
7 | 36564116560125052 |
oct | 3603762675632522 |
9 | 570116677225117 |
10 | 132214511056210 |
11 | 3914494a736550 |
12 | 129b40842a772a |
13 | 58a0a0c5a0bcb |
14 | 2491306039562 |
15 | 104430992c8aa |
hex | 783f96f73552 |
132214511056210 has 64 divisors (see below), whose sum is σ = 261289586139264. Its totient is φ = 47769218380800.
The previous prime is 132214511056207. The next prime is 132214511056211. The reversal of 132214511056210 is 12650115412231.
132214511056210 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (132214511056211) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 60990442 + ... + 63121018.
It is an arithmetic number, because the mean of its divisors is an integer number (4082649783426).
Almost surely, 2132214511056210 is an apocalyptic number.
132214511056210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132214511056210 is a deficient number, since it is larger than the sum of its proper divisors (129075075083054).
132214511056210 is a wasteful number, since it uses less digits than its factorization.
132214511056210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2134219.
The product of its (nonzero) digits is 14400, while the sum is 34.
Adding to 132214511056210 its reverse (12650115412231), we get a palindrome (144864626468441).
The spelling of 132214511056210 in words is "one hundred thirty-two trillion, two hundred fourteen billion, five hundred eleven million, fifty-six thousand, two hundred ten".
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