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132214663021471 is a prime number
BaseRepresentation
bin11110000011111110100000…
…000001100000001110011111
3122100010121011012012111021121
4132003332200001200032133
5114312201112213141341
61145110324440311411
736564123413611342
oct3603764001401637
9570117135174247
10132214663021471
1139144a184a0278
12129b4107172567
1358a0a34c0a494
14249131c2b6459
151044317e494d1
hex783fa006039f

132214663021471 has 2 divisors, whose sum is σ = 132214663021472. Its totient is φ = 132214663021470.

The previous prime is 132214663021391. The next prime is 132214663021499. The reversal of 132214663021471 is 174120366412231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132214663021471 is a prime.

It is a super-3 number, since 3×1322146630214713 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132214663081471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66107331510735 + 66107331510736.

It is an arithmetic number, because the mean of its divisors is an integer number (66107331510736).

Almost surely, 2132214663021471 is an apocalyptic number.

132214663021471 is a deficient number, since it is larger than the sum of its proper divisors (1).

132214663021471 is an equidigital number, since it uses as much as digits as its factorization.

132214663021471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 290304, while the sum is 43.

The spelling of 132214663021471 in words is "one hundred thirty-two trillion, two hundred fourteen billion, six hundred sixty-three million, twenty-one thousand, four hundred seventy-one".