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132216042430817 is a prime number
BaseRepresentation
bin11110000011111111110010…
…001111100010000101100001
3122100010201201022210202011122
4132003333302033202011201
5114312211423330241232
61145111113354022025
736564202533445052
oct3603776217420541
9570121638722148
10132216042430817
11391455660a59a4
12129b4431117915
1358a0bc4929a27
14249140d588729
1510443990c3312
hex783ff23e2161

132216042430817 has 2 divisors, whose sum is σ = 132216042430818. Its totient is φ = 132216042430816.

The previous prime is 132216042430811. The next prime is 132216042430819. The reversal of 132216042430817 is 718034240612231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112617748846801 + 19598293584016 = 10612151^2 + 4426996^2 .

It is an emirp because it is prime and its reverse (718034240612231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132216042430817 - 26 = 132216042430753 is a prime.

Together with 132216042430819, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132216042430811) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66108021215408 + 66108021215409.

It is an arithmetic number, because the mean of its divisors is an integer number (66108021215409).

Almost surely, 2132216042430817 is an apocalyptic number.

It is an amenable number.

132216042430817 is a deficient number, since it is larger than the sum of its proper divisors (1).

132216042430817 is an equidigital number, since it uses as much as digits as its factorization.

132216042430817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 387072, while the sum is 44.

The spelling of 132216042430817 in words is "one hundred thirty-two trillion, two hundred sixteen billion, forty-two million, four hundred thirty thousand, eight hundred seventeen".