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1322202119989 is a prime number
BaseRepresentation
bin10011001111011001011…
…000110011111100110101
311200101211112120000012111
4103033121120303330311
5133130332220314424
62451224500051021
7164345254404232
oct23173130637465
94611745500174
101322202119989
1146a819699593
12194302993a71
13978b5a9664a
1447dd0100789
15245d817b194
hex133d9633f35

1322202119989 has 2 divisors, whose sum is σ = 1322202119990. Its totient is φ = 1322202119988.

The previous prime is 1322202119971. The next prime is 1322202120139. The reversal of 1322202119989 is 9899112022231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1197481547025 + 124720572964 = 1094295^2 + 353158^2 .

It is an emirp because it is prime and its reverse (9899112022231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1322202119989 is a prime.

It is a super-2 number, since 2×13222021199892 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1322202119969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661101059994 + 661101059995.

It is an arithmetic number, because the mean of its divisors is an integer number (661101059995).

Almost surely, 21322202119989 is an apocalyptic number.

It is an amenable number.

1322202119989 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322202119989 is an equidigital number, since it uses as much as digits as its factorization.

1322202119989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 279936, while the sum is 49.

The spelling of 1322202119989 in words is "one trillion, three hundred twenty-two billion, two hundred two million, one hundred nineteen thousand, nine hundred eighty-nine".