Base | Representation |
---|---|
bin | 1100000001101000001010… |
… | …1010000110000100000101 |
3 | 1201211000112222111011200121 |
4 | 3000122002222012010011 |
5 | 3213112330430110203 |
6 | 44042052144341541 |
7 | 2533156666421254 |
oct | 300320252060405 |
9 | 51730488434617 |
10 | 13222101410053 |
11 | 4238509601438 |
12 | 15966470148b1 |
13 | 74bab9b44b03 |
14 | 339d4b52479b |
15 | 17de0d0bc0bd |
hex | c0682a86105 |
13222101410053 has 8 divisors (see below), whose sum is σ = 13317437920640. Its totient is φ = 13126767949440.
The previous prime is 13222101410029. The next prime is 13222101410171. The reversal of 13222101410053 is 35001410122231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13222101410053 - 29 = 13222101409541 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13222101410753) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8328373 + ... + 9788053.
It is an arithmetic number, because the mean of its divisors is an integer number (1664679740080).
Almost surely, 213222101410053 is an apocalyptic number.
It is an amenable number.
13222101410053 is a deficient number, since it is larger than the sum of its proper divisors (95336510587).
13222101410053 is a wasteful number, since it uses less digits than its factorization.
13222101410053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1524987.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 13222101410053 its reverse (35001410122231), we get a palindrome (48223511532284).
The spelling of 13222101410053 in words is "thirteen trillion, two hundred twenty-two billion, one hundred one million, four hundred ten thousand, fifty-three".
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