Base | Representation |
---|---|
bin | 10011001111011001111… |
… | …010101110111010011101 |
3 | 11200101212011021210002121 |
4 | 103033121322232322131 |
5 | 133130342004343003 |
6 | 2451225414422541 |
7 | 164345423111215 |
oct | 23173172567235 |
9 | 4611764253077 |
10 | 1322211012253 |
11 | 46a82371246a |
12 | 194305961a51 |
13 | 978b788ac41 |
14 | 47dd1377245 |
15 | 245d8d35cbd |
hex | 133d9eaee9d |
1322211012253 has 2 divisors, whose sum is σ = 1322211012254. Its totient is φ = 1322211012252.
The previous prime is 1322211012179. The next prime is 1322211012281. The reversal of 1322211012253 is 3522101122231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1028141244729 + 294069767524 = 1013973^2 + 542282^2 .
It is a cyclic number.
It is not a de Polignac number, because 1322211012253 - 221 = 1322208915101 is a prime.
It is a super-2 number, since 2×13222110122532 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1322211018253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661105506126 + 661105506127.
It is an arithmetic number, because the mean of its divisors is an integer number (661105506127).
Almost surely, 21322211012253 is an apocalyptic number.
It is an amenable number.
1322211012253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1322211012253 is an equidigital number, since it uses as much as digits as its factorization.
1322211012253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1322211012253 its reverse (3522101122231), we get a palindrome (4844312134484).
The spelling of 1322211012253 in words is "one trillion, three hundred twenty-two billion, two hundred eleven million, twelve thousand, two hundred fifty-three".
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