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132222003120253 is a prime number
BaseRepresentation
bin11110000100000101010101…
…100001110000100001111101
3122100011022002201220010220001
4132010011111201300201331
5114312311130244322003
61145113541044154301
736564503332456264
oct3604052541604175
9570138081803801
10132222003120253
1139148044817112
12129b5615398991
1358a16348109b7
1424918170835db
1510445e754361d
hex78415587087d

132222003120253 has 2 divisors, whose sum is σ = 132222003120254. Its totient is φ = 132222003120252.

The previous prime is 132222003120241. The next prime is 132222003120301. The reversal of 132222003120253 is 352021300222231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131918157426969 + 303845693284 = 11485563^2 + 551222^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132222003120253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132222003120353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66111001560126 + 66111001560127.

It is an arithmetic number, because the mean of its divisors is an integer number (66111001560127).

Almost surely, 2132222003120253 is an apocalyptic number.

It is an amenable number.

132222003120253 is a deficient number, since it is larger than the sum of its proper divisors (1).

132222003120253 is an equidigital number, since it uses as much as digits as its factorization.

132222003120253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 132222003120253 its reverse (352021300222231), we get a palindrome (484243303342484).

The spelling of 132222003120253 in words is "one hundred thirty-two trillion, two hundred twenty-two billion, three million, one hundred twenty thousand, two hundred fifty-three".