Base | Representation |
---|---|
bin | 11110000100000101011100… |
… | …100100001111101100100011 |
3 | 122100011022101222002212021122 |
4 | 132010011130210033230203 |
5 | 114312311401012301312 |
6 | 1145114000503242455 |
7 | 36564506265314201 |
oct | 3604053444175443 |
9 | 570138358085248 |
10 | 132222121212707 |
11 | 391480a5445789 |
12 | 129b5648a4942b |
13 | 58a165311a5a6 |
14 | 2491828a24071 |
15 | 1044602abdb72 |
hex | 78415c90fb23 |
132222121212707 has 2 divisors, whose sum is σ = 132222121212708. Its totient is φ = 132222121212706.
The previous prime is 132222121212703. The next prime is 132222121212751. The reversal of 132222121212707 is 707212121222231.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (707212121222231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132222121212707 - 22 = 132222121212703 is a prime.
It is not a weakly prime, because it can be changed into another prime (132222121212703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66111060606353 + 66111060606354.
It is an arithmetic number, because the mean of its divisors is an integer number (66111060606354).
Almost surely, 2132222121212707 is an apocalyptic number.
132222121212707 is a deficient number, since it is larger than the sum of its proper divisors (1).
132222121212707 is an equidigital number, since it uses as much as digits as its factorization.
132222121212707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18816, while the sum is 35.
Adding to 132222121212707 its reverse (707212121222231), we get a palindrome (839434242434938).
The spelling of 132222121212707 in words is "one hundred thirty-two trillion, two hundred twenty-two billion, one hundred twenty-one million, two hundred twelve thousand, seven hundred seven".
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