Base | Representation |
---|---|
bin | 11110000100000101101101… |
… | …111010010100101100110010 |
3 | 122100011100011020200012200211 |
4 | 132010011231322110230302 |
5 | 114312313000011304132 |
6 | 1145114045420334334 |
7 | 36564516430631524 |
oct | 3604055572245462 |
9 | 570140136605624 |
10 | 132222412213042 |
11 | 39148234732628 |
12 | 129b570a3a43aa |
13 | 58a169b4b6c38 |
14 | 2491855533a14 |
15 | 104461d401147 |
hex | 78416de94b32 |
132222412213042 has 4 divisors (see below), whose sum is σ = 198333618319566. Its totient is φ = 66111206106520.
The previous prime is 132222412213039. The next prime is 132222412213043. The reversal of 132222412213042 is 240312214222231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 131639618911761 + 582793301281 = 11473431^2 + 763409^2 .
It is a junction number, because it is equal to n+sod(n) for n = 132222412212995 and 132222412213013.
It is not an unprimeable number, because it can be changed into a prime (132222412213043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33055603053259 + ... + 33055603053262.
Almost surely, 2132222412213042 is an apocalyptic number.
132222412213042 is a deficient number, since it is larger than the sum of its proper divisors (66111206106524).
132222412213042 is an equidigital number, since it uses as much as digits as its factorization.
132222412213042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66111206106523.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 132222412213042 its reverse (240312214222231), we get a palindrome (372534626435273).
The spelling of 132222412213042 in words is "one hundred thirty-two trillion, two hundred twenty-two billion, four hundred twelve million, two hundred thirteen thousand, forty-two".
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