Base | Representation |
---|---|
bin | 1100000001101000111100… |
… | …1101110100010110111011 |
3 | 1201211001002122221101202101 |
4 | 3000122033031310112323 |
5 | 3213113243344220212 |
6 | 44042125112244231 |
7 | 2533165135314421 |
oct | 300321715642673 |
9 | 51731078841671 |
10 | 13222312101307 |
11 | 4238607526941 |
12 | 15966a56a0677 |
13 | 74bb216a34aa |
14 | 339d6b4cb111 |
15 | 17de21839157 |
hex | c068f3745bb |
13222312101307 has 2 divisors, whose sum is σ = 13222312101308. Its totient is φ = 13222312101306.
The previous prime is 13222312101289. The next prime is 13222312101359. The reversal of 13222312101307 is 70310121322231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13222312101307 - 27 = 13222312101179 is a prime.
It is a super-2 number, since 2×132223121013072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13222312141307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611156050653 + 6611156050654.
It is an arithmetic number, because the mean of its divisors is an integer number (6611156050654).
Almost surely, 213222312101307 is an apocalyptic number.
13222312101307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13222312101307 is an equidigital number, since it uses as much as digits as its factorization.
13222312101307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 13222312101307 its reverse (70310121322231), we get a palindrome (83532433423538).
The spelling of 13222312101307 in words is "thirteen trillion, two hundred twenty-two billion, three hundred twelve million, one hundred one thousand, three hundred seven".
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