Base | Representation |
---|---|
bin | 11000101000001110… |
… | …11111110100001011 |
3 | 1021010111022002201121 |
4 | 30110013133310023 |
5 | 204034414132111 |
6 | 10024014100111 |
7 | 645443433520 |
oct | 142407376413 |
9 | 37114262647 |
10 | 13222411531 |
11 | 567578553a |
12 | 26901aa637 |
13 | 13294a4c64 |
14 | 8d6103147 |
15 | 525c36871 |
hex | 3141dfd0b |
13222411531 has 4 divisors (see below), whose sum is σ = 15111327472. Its totient is φ = 11333495592.
The previous prime is 13222411523. The next prime is 13222411591. The reversal of 13222411531 is 13511422231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13511422231 = 17 ⋅794789543.
It is a cyclic number.
It is not a de Polignac number, because 13222411531 - 23 = 13222411523 is a prime.
It is a super-2 number, since 2×132224115312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13222411496 and 13222411505.
It is not an unprimeable number, because it can be changed into a prime (13222411591) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 944457960 + ... + 944457973.
It is an arithmetic number, because the mean of its divisors is an integer number (3777831868).
Almost surely, 213222411531 is an apocalyptic number.
13222411531 is a deficient number, since it is larger than the sum of its proper divisors (1888915941).
13222411531 is an equidigital number, since it uses as much as digits as its factorization.
13222411531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1888915940.
The product of its digits is 1440, while the sum is 25.
Adding to 13222411531 its reverse (13511422231), we get a palindrome (26733833762).
The spelling of 13222411531 in words is "thirteen billion, two hundred twenty-two million, four hundred eleven thousand, five hundred thirty-one".
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