Base | Representation |
---|---|
bin | 1100000001101001010100… |
… | …1111010000110010011101 |
3 | 1201211001100201001212011121 |
4 | 3000122111033100302131 |
5 | 3213114000231040242 |
6 | 44042143122050541 |
7 | 2533200503206246 |
oct | 300322517206235 |
9 | 51731321055147 |
10 | 13222413143197 |
11 | 423865956a135 |
12 | 15967134a9a51 |
13 | 74bb395c02ab |
14 | 339d7aaadccd |
15 | 17de2a647667 |
hex | c06953d0c9d |
13222413143197 has 2 divisors, whose sum is σ = 13222413143198. Its totient is φ = 13222413143196.
The previous prime is 13222413143087. The next prime is 13222413143207. The reversal of 13222413143197 is 79134131422231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12540246170841 + 682166972356 = 3541221^2 + 825934^2 .
It is a cyclic number.
It is not a de Polignac number, because 13222413143197 - 215 = 13222413110429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13222413143297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611206571598 + 6611206571599.
It is an arithmetic number, because the mean of its divisors is an integer number (6611206571599).
Almost surely, 213222413143197 is an apocalyptic number.
It is an amenable number.
13222413143197 is a deficient number, since it is larger than the sum of its proper divisors (1).
13222413143197 is an equidigital number, since it uses as much as digits as its factorization.
13222413143197 is an evil number, because the sum of its binary digits is even.
The product of its digits is 217728, while the sum is 43.
The spelling of 13222413143197 in words is "thirteen trillion, two hundred twenty-two billion, four hundred thirteen million, one hundred forty-three thousand, one hundred ninety-seven".
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