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132232012231247 is a prime number
BaseRepresentation
bin11110000100001110101010…
…000111011111001001001111
3122100012020221021210122221122
4132010032222013133021033
5114312442130112344442
61145122314154151155
736565306350506015
oct3604165207371117
9570166837718848
10132232012231247
1139151310694375
12129b75494224bb
1358a256b36b196
1424920c64d88b5
1510449d1100dd2
hex7843aa1df24f

132232012231247 has 2 divisors, whose sum is σ = 132232012231248. Its totient is φ = 132232012231246.

The previous prime is 132232012231219. The next prime is 132232012231343. The reversal of 132232012231247 is 742132210232231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132232012231247 - 230 = 132230938489423 is a prime.

It is a super-2 number, since 2×1322320122312472 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132232012231447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66116006115623 + 66116006115624.

It is an arithmetic number, because the mean of its divisors is an integer number (66116006115624).

Almost surely, 2132232012231247 is an apocalyptic number.

132232012231247 is a deficient number, since it is larger than the sum of its proper divisors (1).

132232012231247 is an equidigital number, since it uses as much as digits as its factorization.

132232012231247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 35.

Adding to 132232012231247 its reverse (742132210232231), we get a palindrome (874364222463478).

The spelling of 132232012231247 in words is "one hundred thirty-two trillion, two hundred thirty-two billion, twelve million, two hundred thirty-one thousand, two hundred forty-seven".