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13223221000471 is a prime number
BaseRepresentation
bin1100000001101100010101…
…1000111111100100010111
31201211010110000012021000101
43000123011120333210113
53213122124034003341
644042355221154531
72533226512656256
oct300330530774427
951733400167011
1013223221000471
114238a33587279
1215968b9b5ba47
1374bc37a94651
1433a0160c279d
1517de76522831
hexc06c563f917

13223221000471 has 2 divisors, whose sum is σ = 13223221000472. Its totient is φ = 13223221000470.

The previous prime is 13223221000403. The next prime is 13223221000481. The reversal of 13223221000471 is 17400012232231.

13223221000471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13223221000471 - 29 = 13223220999959 is a prime.

It is a super-3 number, since 3×132232210004713 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13223221000481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6611610500235 + 6611610500236.

It is an arithmetic number, because the mean of its divisors is an integer number (6611610500236).

Almost surely, 213223221000471 is an apocalyptic number.

13223221000471 is a deficient number, since it is larger than the sum of its proper divisors (1).

13223221000471 is an equidigital number, since it uses as much as digits as its factorization.

13223221000471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 28.

The spelling of 13223221000471 in words is "thirteen trillion, two hundred twenty-three billion, two hundred twenty-one million, four hundred seventy-one", and thus it is an aban number.