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132233141041 is a prime number
BaseRepresentation
bin111101100100110110…
…1011001101100110001
3110122022112222120020021
41323021231121230301
54131303141003131
6140425211043441
712360601103431
oct1731155315461
9418275876207
10132233141041
1151097185041
1221764740581
13c61473aa71
146585cd22c1
15368de29e11
hex1ec9b59b31

132233141041 has 2 divisors, whose sum is σ = 132233141042. Its totient is φ = 132233141040.

The previous prime is 132233141039. The next prime is 132233141077. The reversal of 132233141041 is 140141332231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130323888016 + 1909253025 = 361004^2 + 43695^2 .

It is a cyclic number.

It is not a de Polignac number, because 132233141041 - 21 = 132233141039 is a prime.

Together with 132233141039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 132233140997 and 132233141015.

It is not a weakly prime, because it can be changed into another prime (132233141021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66116570520 + 66116570521.

It is an arithmetic number, because the mean of its divisors is an integer number (66116570521).

Almost surely, 2132233141041 is an apocalyptic number.

It is an amenable number.

132233141041 is a deficient number, since it is larger than the sum of its proper divisors (1).

132233141041 is an equidigital number, since it uses as much as digits as its factorization.

132233141041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 132233141041 its reverse (140141332231), we get a palindrome (272374473272).

The spelling of 132233141041 in words is "one hundred thirty-two billion, two hundred thirty-three million, one hundred forty-one thousand, forty-one".