Base | Representation |
---|---|
bin | 11110000100001111111110… |
… | …110011101011011010111101 |
3 | 122100012101121022102101012211 |
4 | 132010033332303223122331 |
5 | 114313003032333231023 |
6 | 1145123111152300421 |
7 | 36565356512635255 |
oct | 3604177663533275 |
9 | 570171538371184 |
10 | 132233433102013 |
11 | 3915197a738631 |
12 | 129b7885241711 |
13 | 58a2736846509 |
14 | 24921bd0c0965 |
15 | 1044a65c19a0d |
hex | 7843feceb6bd |
132233433102013 has 2 divisors, whose sum is σ = 132233433102014. Its totient is φ = 132233433102012.
The previous prime is 132233433101941. The next prime is 132233433102167. The reversal of 132233433102013 is 310201334332231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74534870356164 + 57698562745849 = 8633358^2 + 7595957^2 .
It is a cyclic number.
It is not a de Polignac number, because 132233433102013 - 217 = 132233432970941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132233433802013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66116716551006 + 66116716551007.
It is an arithmetic number, because the mean of its divisors is an integer number (66116716551007).
Almost surely, 2132233433102013 is an apocalyptic number.
It is an amenable number.
132233433102013 is a deficient number, since it is larger than the sum of its proper divisors (1).
132233433102013 is an equidigital number, since it uses as much as digits as its factorization.
132233433102013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 31.
Adding to 132233433102013 its reverse (310201334332231), we get a palindrome (442434767434244).
The spelling of 132233433102013 in words is "one hundred thirty-two trillion, two hundred thirty-three billion, four hundred thirty-three million, one hundred two thousand, thirteen".
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