Base | Representation |
---|---|
bin | 11110000100011010001100… |
… | …100111111100001100010111 |
3 | 122100020102220202221121021222 |
4 | 132010122030213330030113 |
5 | 114313143013443333442 |
6 | 1145132123441000555 |
7 | 36566225366533103 |
oct | 3604321447741427 |
9 | 570212822847258 |
10 | 132244402324247 |
11 | 39156599564654 |
12 | 129b9a2692315b |
13 | 58a3794285b65 |
14 | 249293dc5c903 |
15 | 1044ea8c298d2 |
hex | 78468c9fc317 |
132244402324247 has 2 divisors, whose sum is σ = 132244402324248. Its totient is φ = 132244402324246.
The previous prime is 132244402324157. The next prime is 132244402324277. The reversal of 132244402324247 is 742423204442231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132244402324247 - 234 = 132227222455063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132244402324198 and 132244402324207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132244402324277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66122201162123 + 66122201162124.
It is an arithmetic number, because the mean of its divisors is an integer number (66122201162124).
Almost surely, 2132244402324247 is an apocalyptic number.
132244402324247 is a deficient number, since it is larger than the sum of its proper divisors (1).
132244402324247 is an equidigital number, since it uses as much as digits as its factorization.
132244402324247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2064384, while the sum is 44.
Adding to 132244402324247 its reverse (742423204442231), we get a palindrome (874667606766478).
The spelling of 132244402324247 in words is "one hundred thirty-two trillion, two hundred forty-four billion, four hundred two million, three hundred twenty-four thousand, two hundred forty-seven".
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