Search a number
-
+
132244413133142 = 266122206566571
BaseRepresentation
bin11110000100011010001101…
…010001001011000101010110
3122100020102221112021202022102
4132010122031101023011112
5114313143024230230032
61145132124504402102
736566225560441652
oct3604321521130526
9570212845252272
10132244413133142
11391565a4677522
12129b9a2a476332
1358a379659b95b
142492941473a62
151044ea9b62362
hex78468d44b156

132244413133142 has 4 divisors (see below), whose sum is σ = 198366619699716. Its totient is φ = 66122206566570.

The previous prime is 132244413133127. The next prime is 132244413133153. The reversal of 132244413133142 is 241331314442231.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 132244413133096 and 132244413133105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33061103283284 + ... + 33061103283287.

It is an arithmetic number, because the mean of its divisors is an integer number (49591654924929).

Almost surely, 2132244413133142 is an apocalyptic number.

132244413133142 is a deficient number, since it is larger than the sum of its proper divisors (66122206566574).

132244413133142 is an equidigital number, since it uses as much as digits as its factorization.

132244413133142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66122206566573.

The product of its digits is 165888, while the sum is 38.

Adding to 132244413133142 its reverse (241331314442231), we get a palindrome (373575727575373).

The spelling of 132244413133142 in words is "one hundred thirty-two trillion, two hundred forty-four billion, four hundred thirteen million, one hundred thirty-three thousand, one hundred forty-two".

Divisors: 1 2 66122206566571 132244413133142