1322525242331 has 2 divisors, whose sum is σ = 1322525242332. Its totient is φ = 1322525242330.

The previous prime is 1322525242277. The next prime is 1322525242333. The reversal of 1322525242331 is 1332425252231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1322525242331 - 2¹⁰ = 1322525241307 is a prime.

It is a super-2 number, since 2×1322525242331² (a number of 25 digits) contains 22 as substring.

Together with 1322525242333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1322525242291 and 1322525242300.

It is not a weakly prime, because it can be changed into another prime (1322525242333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661262621165 + 661262621166.

It is an arithmetic number, because the mean of its divisors is an integer number (661262621166).

Almost surely, 2^{1322525242331} is an apocalyptic number.

1322525242331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322525242331 is an equidigital number, since it uses as much as digits as its factorization.

1322525242331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 86400, while the sum is 35.

The spelling of 1322525242331 in words is "one trillion, three hundred twenty-two billion, five hundred twenty-five million, two hundred forty-two thousand, three hundred thirty-one".