Base | Representation |
---|---|
bin | 1100000001110100010010… |
… | …0111101000001111101111 |
3 | 1201211022221202201021121220 |
4 | 3000131010213220033233 |
5 | 3213141012004343120 |
6 | 44043351111554423 |
7 | 2533333432203012 |
oct | 300350447501757 |
9 | 51738852637556 |
10 | 13225355543535 |
11 | 4239929469053 |
12 | 15971b498ba13 |
13 | 74c1b8088295 |
14 | 33a1797a1379 |
15 | 17e04db0eb40 |
hex | c07449e83ef |
13225355543535 has 16 divisors (see below), whose sum is σ = 21162199048704. Its totient is φ = 7052979563552.
The previous prime is 13225355543503. The next prime is 13225355543537. The reversal of 13225355543535 is 53534555352231.
13225355543535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13225355543535 - 25 = 13225355543503 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13225355543537) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33760827 + ... + 34150316.
It is an arithmetic number, because the mean of its divisors is an integer number (1322637440544).
Almost surely, 213225355543535 is an apocalyptic number.
13225355543535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13225355543535 is a deficient number, since it is larger than the sum of its proper divisors (7936843505169).
13225355543535 is a wasteful number, since it uses less digits than its factorization.
13225355543535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67924134.
The product of its digits is 20250000, while the sum is 51.
The spelling of 13225355543535 in words is "thirteen trillion, two hundred twenty-five billion, three hundred fifty-five million, five hundred forty-three thousand, five hundred thirty-five".
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