Base | Representation |
---|---|
bin | 11110000100100010110100… |
… | …001001010101001011010001 |
3 | 122100021022210122002122211021 |
4 | 132010202310021111023101 |
5 | 114313320441230321340 |
6 | 1145140253540515441 |
7 | 36600003603656623 |
oct | 3604426411251321 |
9 | 570238718078737 |
10 | 132253655323345 |
11 | 3915a507647846 |
12 | 129bb7896abb81 |
13 | 58a460a28895a |
14 | 249317aad0c13 |
15 | 104534b22de4a |
hex | 7848b42552d1 |
132253655323345 has 8 divisors (see below), whose sum is σ = 158707855535040. Its totient is φ = 105800611494000.
The previous prime is 132253655323331. The next prime is 132253655323421. The reversal of 132253655323345 is 543323556352231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132253655323345 - 27 = 132253655323217 is a prime.
It is a super-2 number, since 2×1322536553233452 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132253655323292 and 132253655323301.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 288843955 + ... + 289301464.
It is an arithmetic number, because the mean of its divisors is an integer number (19838481941880).
Almost surely, 2132253655323345 is an apocalyptic number.
It is an amenable number.
132253655323345 is a deficient number, since it is larger than the sum of its proper divisors (26454200211695).
132253655323345 is an equidigital number, since it uses as much as digits as its factorization.
132253655323345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 578191175.
The product of its digits is 29160000, while the sum is 52.
The spelling of 132253655323345 in words is "one hundred thirty-two trillion, two hundred fifty-three billion, six hundred fifty-five million, three hundred twenty-three thousand, three hundred forty-five".
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