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132253655323345 = 545751578145419
BaseRepresentation
bin11110000100100010110100…
…001001010101001011010001
3122100021022210122002122211021
4132010202310021111023101
5114313320441230321340
61145140253540515441
736600003603656623
oct3604426411251321
9570238718078737
10132253655323345
113915a507647846
12129bb7896abb81
1358a460a28895a
14249317aad0c13
15104534b22de4a
hex7848b42552d1

132253655323345 has 8 divisors (see below), whose sum is σ = 158707855535040. Its totient is φ = 105800611494000.

The previous prime is 132253655323331. The next prime is 132253655323421. The reversal of 132253655323345 is 543323556352231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 132253655323345 - 27 = 132253655323217 is a prime.

It is a super-2 number, since 2×1322536553233452 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132253655323292 and 132253655323301.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 288843955 + ... + 289301464.

It is an arithmetic number, because the mean of its divisors is an integer number (19838481941880).

Almost surely, 2132253655323345 is an apocalyptic number.

It is an amenable number.

132253655323345 is a deficient number, since it is larger than the sum of its proper divisors (26454200211695).

132253655323345 is an equidigital number, since it uses as much as digits as its factorization.

132253655323345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 578191175.

The product of its digits is 29160000, while the sum is 52.

The spelling of 132253655323345 in words is "one hundred thirty-two trillion, two hundred fifty-three billion, six hundred fifty-five million, three hundred twenty-three thousand, three hundred forty-five".

Divisors: 1 5 45751 228755 578145419 2890727095 26450731064669 132253655323345