Base | Representation |
---|---|
bin | 11110000100100010110100… |
… | …001001010101010010110111 |
3 | 122100021022210122002200111021 |
4 | 132010202310021111102313 |
5 | 114313320441230330311 |
6 | 1145140253540522011 |
7 | 36600003603661216 |
oct | 3604426411252267 |
9 | 570238718080437 |
10 | 132253655323831 |
11 | 3915a507648148 |
12 | 129bb7896b0307 |
13 | 58a460a288c42 |
14 | 249317aad107d |
15 | 104534b22e171 |
hex | 7848b42554b7 |
132253655323831 has 2 divisors, whose sum is σ = 132253655323832. Its totient is φ = 132253655323830.
The previous prime is 132253655323763. The next prime is 132253655323871. The reversal of 132253655323831 is 138323556352231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132253655323831 - 29 = 132253655323319 is a prime.
It is a super-2 number, since 2×1322536553238312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132253655323871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66126827661915 + 66126827661916.
It is an arithmetic number, because the mean of its divisors is an integer number (66126827661916).
Almost surely, 2132253655323831 is an apocalyptic number.
132253655323831 is a deficient number, since it is larger than the sum of its proper divisors (1).
132253655323831 is an equidigital number, since it uses as much as digits as its factorization.
132253655323831 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11664000, while the sum is 52.
The spelling of 132253655323831 in words is "one hundred thirty-two trillion, two hundred fifty-three billion, six hundred fifty-five million, three hundred twenty-three thousand, eight hundred thirty-one".
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