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132254150623351 = 612168100829891
BaseRepresentation
bin11110000100100011010001…
…101010110000000001110111
3122100021101002011002111200221
4132010203101222300001313
5114313323000024421401
61145140415032515211
736600022066650151
oct3604432152600167
9570241064074627
10132254150623351
113915a741193a99
12129bb8a754bb07
1358a4688a86693
1424931c67c1ad1
1510453799697a1
hex7848d1ab0077

132254150623351 has 4 divisors (see below), whose sum is σ = 134422251453304. Its totient is φ = 130086049793400.

The previous prime is 132254150623337. The next prime is 132254150623367. The reversal of 132254150623351 is 153326051452231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132254150623351 - 25 = 132254150623319 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132254150623298 and 132254150623307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132254150623381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1084050414885 + ... + 1084050415006.

It is an arithmetic number, because the mean of its divisors is an integer number (33605562863326).

Almost surely, 2132254150623351 is an apocalyptic number.

132254150623351 is a deficient number, since it is larger than the sum of its proper divisors (2168100829953).

132254150623351 is an equidigital number, since it uses as much as digits as its factorization.

132254150623351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2168100829952.

The product of its (nonzero) digits is 648000, while the sum is 43.

The spelling of 132254150623351 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, one hundred fifty million, six hundred twenty-three thousand, three hundred fifty-one".

Divisors: 1 61 2168100829891 132254150623351