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1322613542561 is a prime number
BaseRepresentation
bin10011001111110001111…
…010010000111010100001
311200102220012201102212112
4103033301322100322201
5133132203031330221
62451333354205105
7164361411422033
oct23176172207241
94612805642775
101322613542561
1146aa0a956443
121943b8723795
13979500a715c
144802c9d9c53
152460e34915b
hex133f1e90ea1

1322613542561 has 2 divisors, whose sum is σ = 1322613542562. Its totient is φ = 1322613542560.

The previous prime is 1322613542543. The next prime is 1322613542563. The reversal of 1322613542561 is 1652453162231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1322454000400 + 159542161 = 1149980^2 + 12631^2 .

It is an emirp because it is prime and its reverse (1652453162231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1322613542561 - 214 = 1322613526177 is a prime.

Together with 1322613542563, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1322613542563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661306771280 + 661306771281.

It is an arithmetic number, because the mean of its divisors is an integer number (661306771281).

Almost surely, 21322613542561 is an apocalyptic number.

It is an amenable number.

1322613542561 is a deficient number, since it is larger than the sum of its proper divisors (1).

1322613542561 is an equidigital number, since it uses as much as digits as its factorization.

1322613542561 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 259200, while the sum is 41.

The spelling of 1322613542561 in words is "one trillion, three hundred twenty-two billion, six hundred thirteen million, five hundred forty-two thousand, five hundred sixty-one".