Base | Representation |
---|---|
bin | 11110000100101100010010… |
… | …011000100011101010100110 |
3 | 122100022022001110121012110101 |
4 | 132010230102120203222212 |
5 | 114314002304013322000 |
6 | 1145145055112214314 |
7 | 36600513625630444 |
oct | 3604542230435246 |
9 | 570268043535411 |
10 | 132263826307750 |
11 | 39163856926985 |
12 | 12a0174799a39a |
13 | 58a556b511517 |
14 | 2493863841b94 |
15 | 1045744113e6a |
hex | 784b12623aa6 |
132263826307750 has 16 divisors (see below), whose sum is σ = 247597882848576. Its totient is φ = 52905530523000.
The previous prime is 132263826307619. The next prime is 132263826307801. The reversal of 132263826307750 is 57703628362231.
It is a junction number, because it is equal to n+sod(n) for n = 132263826307691 and 132263826307700.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 264527652366 + ... + 264527652865.
It is an arithmetic number, because the mean of its divisors is an integer number (15474867678036).
Almost surely, 2132263826307750 is an apocalyptic number.
132263826307750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132263826307750 is a deficient number, since it is larger than the sum of its proper divisors (115334056540826).
132263826307750 is an equidigital number, since it uses as much as digits as its factorization.
132263826307750 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 529055305248 (or 529055305238 counting only the distinct ones).
The product of its (nonzero) digits is 15240960, while the sum is 55.
The spelling of 132263826307750 in words is "one hundred thirty-two trillion, two hundred sixty-three billion, eight hundred twenty-six million, three hundred seven thousand, seven hundred fifty".
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