Base | Representation |
---|---|
bin | 11110000101001110000101… |
… | …101010110100001000011101 |
3 | 122100102202201211222120100012 |
4 | 132011032011222310020131 |
5 | 114320101121233240442 |
6 | 1145213500340413005 |
7 | 36603240212005403 |
oct | 3605160552641035 |
9 | 570382654876305 |
10 | 132300120211997 |
11 | 39178190891371 |
12 | 12a087966a7165 |
13 | 58a8b038176ca |
14 | 2495507b23473 |
15 | 104666a57d582 |
hex | 785385ab421d |
132300120211997 has 2 divisors, whose sum is σ = 132300120211998. Its totient is φ = 132300120211996.
The previous prime is 132300120211957. The next prime is 132300120212023. The reversal of 132300120211997 is 799112021003231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130600692500356 + 1699427711641 = 11428066^2 + 1303621^2 .
It is a cyclic number.
It is not a de Polignac number, because 132300120211997 - 212 = 132300120207901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132300120211937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66150060105998 + 66150060105999.
It is an arithmetic number, because the mean of its divisors is an integer number (66150060105999).
Almost surely, 2132300120211997 is an apocalyptic number.
It is an amenable number.
132300120211997 is a deficient number, since it is larger than the sum of its proper divisors (1).
132300120211997 is an equidigital number, since it uses as much as digits as its factorization.
132300120211997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 41.
The spelling of 132300120211997 in words is "one hundred thirty-two trillion, three hundred billion, one hundred twenty million, two hundred eleven thousand, nine hundred ninety-seven".
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