13230042003403 has 4 divisors (see below), whose sum is σ = 13241417793048. Its totient is φ = 13218666213760.

The previous prime is 13230042003391. The next prime is 13230042003427. The reversal of 13230042003403 is 30430024003231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13230042003403 is a prime.

It is a super-2 number, since 2×13230042003403² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13230042003473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5687893078 + ... + 5687895403.

It is an arithmetic number, because the mean of its divisors is an integer number (3310354448262).

Almost surely, 2^{13230042003403} is an apocalyptic number.

13230042003403 is a deficient number, since it is larger than the sum of its proper divisors (11375789645).

13230042003403 is a wasteful number, since it uses less digits than its factorization.

13230042003403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11375789644.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 13230042003403 its reverse (30430024003231), we get a palindrome (43660066006634).

The spelling of 13230042003403 in words is "thirteen trillion, two hundred thirty billion, forty-two million, three thousand, four hundred three".