Base | Representation |
---|---|
bin | 10011010000001001101… |
… | …010010011110001100101 |
3 | 11200110220222111211202202 |
4 | 103100021222103301211 |
5 | 133134012033410112 |
6 | 2451441110544245 |
7 | 164404320363632 |
oct | 23201152236145 |
9 | 4613828454682 |
10 | 1323012013157 |
11 | 4700a487728a |
12 | 1944aa068085 |
13 | 979b4801583 |
14 | 480698c3189 |
15 | 246343096c2 |
hex | 13409a93c65 |
1323012013157 has 2 divisors, whose sum is σ = 1323012013158. Its totient is φ = 1323012013156.
The previous prime is 1323012013151. The next prime is 1323012013171. The reversal of 1323012013157 is 7513102103231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1321651436161 + 1360576996 = 1149631^2 + 36886^2 .
It is a cyclic number.
It is not a de Polignac number, because 1323012013157 - 26 = 1323012013093 is a prime.
It is a super-2 number, since 2×13230120131572 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323012013151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661506006578 + 661506006579.
It is an arithmetic number, because the mean of its divisors is an integer number (661506006579).
Almost surely, 21323012013157 is an apocalyptic number.
It is an amenable number.
1323012013157 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323012013157 is an equidigital number, since it uses as much as digits as its factorization.
1323012013157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780, while the sum is 29.
Adding to 1323012013157 its reverse (7513102103231), we get a palindrome (8836114116388).
The spelling of 1323012013157 in words is "one trillion, three hundred twenty-three billion, twelve million, thirteen thousand, one hundred fifty-seven".
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