Base | Representation |
---|---|
bin | 1100000010000110000010… |
… | …0111111000101111011001 |
3 | 1201211210020211112001012101 |
4 | 3000201200213320233121 |
5 | 3213230241301343231 |
6 | 44045500002043401 |
7 | 2533562500254124 |
oct | 300414047705731 |
9 | 51753224461171 |
10 | 13230120340441 |
11 | 4240954029534 |
12 | 1598104649561 |
13 | 74c797285534 |
14 | 33a4ac5193bb |
15 | 17e22c0a6661 |
hex | c08609f8bd9 |
13230120340441 has 2 divisors, whose sum is σ = 13230120340442. Its totient is φ = 13230120340440.
The previous prime is 13230120340429. The next prime is 13230120340457. The reversal of 13230120340441 is 14404302103231.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9767525092416 + 3462595248025 = 3125304^2 + 1860805^2 .
It is a cyclic number.
It is not a de Polignac number, because 13230120340441 - 215 = 13230120307673 is a prime.
It is not a weakly prime, because it can be changed into another prime (13230120340471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615060170220 + 6615060170221.
It is an arithmetic number, because the mean of its divisors is an integer number (6615060170221).
Almost surely, 213230120340441 is an apocalyptic number.
It is an amenable number.
13230120340441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13230120340441 is an equidigital number, since it uses as much as digits as its factorization.
13230120340441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 13230120340441 its reverse (14404302103231), we get a palindrome (27634422443672).
The spelling of 13230120340441 in words is "thirteen trillion, two hundred thirty billion, one hundred twenty million, three hundred forty thousand, four hundred forty-one".
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