Base | Representation |
---|---|
bin | 10011010000001001101… |
… | …110001110011111100101 |
3 | 11200110221001110000110201 |
4 | 103100021232032133211 |
5 | 133134012314240401 |
6 | 2451441144550501 |
7 | 164404332201634 |
oct | 23201156163745 |
9 | 4613831400421 |
10 | 1323013040101 |
11 | 4700a54088a5 |
12 | 1944aa482431 |
13 | 979b4aa0b2c |
14 | 48069aad51b |
15 | 2463445db01 |
hex | 13409b8e7e5 |
1323013040101 has 4 divisors (see below), whose sum is σ = 1323037768972. Its totient is φ = 1322988311232.
The previous prime is 1323013040081. The next prime is 1323013040159. The reversal of 1323013040101 is 1010403103231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 970764855076 + 352248185025 = 985274^2 + 593505^2 .
It is a cyclic number.
It is not a de Polignac number, because 1323013040101 - 29 = 1323013039589 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1323013041101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12284010 + ... + 12391243.
It is an arithmetic number, because the mean of its divisors is an integer number (330759442243).
Almost surely, 21323013040101 is an apocalyptic number.
It is an amenable number.
1323013040101 is a deficient number, since it is larger than the sum of its proper divisors (24728871).
1323013040101 is an equidigital number, since it uses as much as digits as its factorization.
1323013040101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24728870.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1323013040101 its reverse (1010403103231), we get a palindrome (2333416143332).
The spelling of 1323013040101 in words is "one trillion, three hundred twenty-three billion, thirteen million, forty thousand, one hundred one".
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