Base | Representation |
---|---|
bin | 11000101001001010… |
… | …10000100000001100 |
3 | 1021011000222110111210 |
4 | 30110211100200030 |
5 | 204043413310012 |
6 | 10024453214420 |
7 | 645566645643 |
oct | 142445204014 |
9 | 37130873453 |
10 | 13230213132 |
11 | 567a123a44 |
12 | 2692931410 |
13 | 132aca6ca6 |
14 | 8d717435a |
15 | 52677823c |
hex | 31495080c |
13230213132 has 24 divisors (see below), whose sum is σ = 30912633136. Its totient is φ = 4404051648.
The previous prime is 13230213131. The next prime is 13230213149. The reversal of 13230213132 is 23131203231.
It is a junction number, because it is equal to n+sod(n) for n = 13230213099 and 13230213108.
It is not an unprimeable number, because it can be changed into a prime (13230213131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 743263 + ... + 760854.
Almost surely, 213230213132 is an apocalyptic number.
13230213132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13230213132 is an abundant number, since it is smaller than the sum of its proper divisors (17682420004).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13230213132 is a wasteful number, since it uses less digits than its factorization.
13230213132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1504857 (or 1504855 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 13230213132 its reverse (23131203231), we get a palindrome (36361416363).
Subtracting 13230213132 from its reverse (23131203231), we obtain a palindrome (9900990099).
The spelling of 13230213132 in words is "thirteen billion, two hundred thirty million, two hundred thirteen thousand, one hundred thirty-two".
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