Search a number
-
+
132302210342023 is a prime number
BaseRepresentation
bin11110000101010000000010…
…010000000001110010000111
3122100102222010111221011201101
4132011100002100001302013
5114320114411321421043
61145214444003240531
736603343051554061
oct3605200220016207
9570388114834641
10132302210342023
1139179063698a57
1212a0907a679147
1358a907785ac37
142495665560731
15104673dce624d
hex785402401c87

132302210342023 has 2 divisors, whose sum is σ = 132302210342024. Its totient is φ = 132302210342022.

The previous prime is 132302210341919. The next prime is 132302210342069. The reversal of 132302210342023 is 320243012203231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132302210342023 is a prime.

It is a super-2 number, since 2×1323022103420232 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132302210341982 and 132302210342000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132302210346023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66151105171011 + 66151105171012.

It is an arithmetic number, because the mean of its divisors is an integer number (66151105171012).

Almost surely, 2132302210342023 is an apocalyptic number.

132302210342023 is a deficient number, since it is larger than the sum of its proper divisors (1).

132302210342023 is an equidigital number, since it uses as much as digits as its factorization.

132302210342023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 132302210342023 its reverse (320243012203231), we get a palindrome (452545222545254).

The spelling of 132302210342023 in words is "one hundred thirty-two trillion, three hundred two billion, two hundred ten million, three hundred forty-two thousand, twenty-three".