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132303111000000 = 2635644101037
BaseRepresentation
bin11110000101010000110111…
…111011110000111111000000
3122100110001110021200100012020
4132011100313323300333000
5114320123232404000000
61145215113215401440
736603404266203063
oct3605206773607700
9570401407610166
10132303111000000
113917948602a696
1212a09290223280
1358a918c324c55
14249570d00c8da
151046792e02ba0
hex785437ef0fc0

132303111000000 has 196 divisors, whose sum is σ = 437559385574424. Its totient is φ = 35280828800000.

The previous prime is 132303110999897. The next prime is 132303111000007. The reversal of 132303111000000 is 111303231.

It is a super-2 number, since 2×1323031110000002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132303111000007) by changing a digit.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 19050519 + ... + 25050518.

Almost surely, 2132303111000000 is an apocalyptic number.

132303111000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132303111000000 is an abundant number, since it is smaller than the sum of its proper divisors (305256274574424).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132303111000000 is an frugal number, since it uses more digits than its factorization.

132303111000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44101082 (or 44101047 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 132303111000000 its reverse (111303231), we get a palindrome (132303222303231).

The spelling of 132303111000000 in words is "one hundred thirty-two trillion, three hundred three billion, one hundred eleven million", and thus it is an aban number.