Base | Representation |
---|---|
bin | 10011010000001010110… |
… | …100011010101100010111 |
3 | 11200110222100001211121001 |
4 | 103100022310122230113 |
5 | 133134032022041101 |
6 | 2451443043204131 |
7 | 164404644455251 |
oct | 23201264325427 |
9 | 4613870054531 |
10 | 1323031440151 |
11 | 470104836053 |
12 | 1944b4676647 |
13 | 979b8843c35 |
14 | 4806c2dccd1 |
15 | 24635d95901 |
hex | 1340ad1ab17 |
1323031440151 has 8 divisors (see below), whose sum is σ = 1344674973600. Its totient is φ = 1301551254528.
The previous prime is 1323031440131. The next prime is 1323031440169. The reversal of 1323031440151 is 1510441303231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1323031440151 - 211 = 1323031438103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1323031440131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40820626 + ... + 40853023.
It is an arithmetic number, because the mean of its divisors is an integer number (168084371700).
Almost surely, 21323031440151 is an apocalyptic number.
1323031440151 is a deficient number, since it is larger than the sum of its proper divisors (21643533449).
1323031440151 is an equidigital number, since it uses as much as digits as its factorization.
1323031440151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81673913.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 1323031440151 its reverse (1510441303231), we get a palindrome (2833472743382).
The spelling of 1323031440151 in words is "one trillion, three hundred twenty-three billion, thirty-one million, four hundred forty thousand, one hundred fifty-one".
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