1323032001113 has 4 divisors (see below), whose sum is σ = 1323529571280. Its totient is φ = 1322534430948.

The previous prime is 1323032001091. The next prime is 1323032001121. The reversal of 1323032001113 is 3111002303231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1323032001113 - 2¹⁸ = 1323031738969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1323032001133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248781095 + ... + 248786412.

It is an arithmetic number, because the mean of its divisors is an integer number (330882392820).

Almost surely, 2^{1323032001113} is an apocalyptic number.

It is an amenable number.

1323032001113 is a deficient number, since it is larger than the sum of its proper divisors (497570167).

1323032001113 is an equidigital number, since it uses as much as digits as its factorization.

1323032001113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 497570166.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 1323032001113 its reverse (3111002303231), we get a palindrome (4434034304344).

The spelling of 1323032001113 in words is "one trillion, three hundred twenty-three billion, thirty-two million, one thousand, one hundred thirteen".