Base | Representation |
---|---|
bin | 11110000101010001110011… |
… | …101000001100010101110011 |
3 | 122100110011001002011220211202 |
4 | 132011101303220030111303 |
5 | 114320132310300032011 |
6 | 1145215400433201415 |
7 | 36603441146631263 |
oct | 3605216350142563 |
9 | 570404032156752 |
10 | 132304112502131 |
11 | 3917994a389aa9 |
12 | 12a0950b70026b |
13 | 58a92bb969a6b |
14 | 24957a602b7a3 |
15 | 1046800cce23b |
hex | 785473a0c573 |
132304112502131 has 4 divisors (see below), whose sum is σ = 132535818479064. Its totient is φ = 132072406525200.
The previous prime is 132304112502119. The next prime is 132304112502269. The reversal of 132304112502131 is 131205211403231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132304112502131 - 210 = 132304112501107 is a prime.
It is a super-2 number, since 2×1323041125021312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132304112502094 and 132304112502103.
It is not an unprimeable number, because it can be changed into a prime (132304112502031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115852987610 + ... + 115852988751.
It is an arithmetic number, because the mean of its divisors is an integer number (33133954619766).
Almost surely, 2132304112502131 is an apocalyptic number.
132304112502131 is a deficient number, since it is larger than the sum of its proper divisors (231705976933).
132304112502131 is an equidigital number, since it uses as much as digits as its factorization.
132304112502131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 231705976932.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 132304112502131 its reverse (131205211403231), we get a palindrome (263509323905362).
The spelling of 132304112502131 in words is "one hundred thirty-two trillion, three hundred four billion, one hundred twelve million, five hundred two thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •