Base | Representation |
---|---|
bin | 11110000101010001110100… |
… | …101111101110110010010101 |
3 | 122100110011002101110200112221 |
4 | 132011101310233232302111 |
5 | 114320132330100133240 |
6 | 1145215402343142341 |
7 | 36603441465215542 |
oct | 3605216457566225 |
9 | 570404071420487 |
10 | 132304131255445 |
11 | 39179959a28706 |
12 | 12a09515a449b1 |
13 | 58a92c28048b6 |
14 | 24957a870dbc9 |
15 | 1046802785a4a |
hex | 785474beec95 |
132304131255445 has 32 divisors (see below), whose sum is σ = 160232042483712. Its totient is φ = 104867606333952.
The previous prime is 132304131255353. The next prime is 132304131255479. The reversal of 132304131255445 is 544552131403231.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132304131255445 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1405156489 + ... + 1405250641.
It is an arithmetic number, because the mean of its divisors is an integer number (5007251327616).
Almost surely, 2132304131255445 is an apocalyptic number.
It is an amenable number.
132304131255445 is a deficient number, since it is larger than the sum of its proper divisors (27927911228267).
132304131255445 is a wasteful number, since it uses less digits than its factorization.
132304131255445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97261.
The product of its (nonzero) digits is 864000, while the sum is 43.
Adding to 132304131255445 its reverse (544552131403231), we get a palindrome (676856262658676).
The spelling of 132304131255445 in words is "one hundred thirty-two trillion, three hundred four billion, one hundred thirty-one million, two hundred fifty-five thousand, four hundred forty-five".
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