Base | Representation |
---|---|
bin | 1100000010000111001010… |
… | …1000001010100010110011 |
3 | 1201211211000212220102110212 |
4 | 3000201302220022202303 |
5 | 3213231401113401001 |
6 | 44045545552214335 |
7 | 2533603125614534 |
oct | 300416250124263 |
9 | 51754025812425 |
10 | 13230422403251 |
11 | 4240a99591819 |
12 | 159818983a3ab |
13 | 74c814a26221 |
14 | 33a4da6a868b |
15 | 17e2488717bb |
hex | c0872a0a8b3 |
13230422403251 has 2 divisors, whose sum is σ = 13230422403252. Its totient is φ = 13230422403250.
The previous prime is 13230422403221. The next prime is 13230422403259. The reversal of 13230422403251 is 15230422403231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13230422403251 - 230 = 13229348661427 is a prime.
It is not a weakly prime, because it can be changed into another prime (13230422403259) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615211201625 + 6615211201626.
It is an arithmetic number, because the mean of its divisors is an integer number (6615211201626).
Almost surely, 213230422403251 is an apocalyptic number.
13230422403251 is a deficient number, since it is larger than the sum of its proper divisors (1).
13230422403251 is an equidigital number, since it uses as much as digits as its factorization.
13230422403251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 13230422403251 its reverse (15230422403231), we get a palindrome (28460844806482).
The spelling of 13230422403251 in words is "thirteen trillion, two hundred thirty billion, four hundred twenty-two million, four hundred three thousand, two hundred fifty-one".
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