1323068161117 has 2 divisors, whose sum is σ = 1323068161118. Its totient is φ = 1323068161116.

The previous prime is 1323068161003. The next prime is 1323068161123. The reversal of 1323068161117 is 7111618603231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1023039194116 + 300028967001 = 1011454^2 + 547749^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1323068161117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1323068161117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323068131117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661534080558 + 661534080559.

It is an arithmetic number, because the mean of its divisors is an integer number (661534080559).

Almost surely, 2^{1323068161117} is an apocalyptic number.

It is an amenable number.

1323068161117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323068161117 is an equidigital number, since it uses as much as digits as its factorization.

1323068161117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36288, while the sum is 40.

The spelling of 1323068161117 in words is "one trillion, three hundred twenty-three billion, sixty-eight million, one hundred sixty-one thousand, one hundred seventeen".