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1323100132322 = 2661550066161
BaseRepresentation
bin10011010000001110111…
…010011101001111100010
311200111011010022202112112
4103100032322131033202
5133134202113213242
62451453535355322
7164406440364053
oct23201672351742
94614133282475
101323100132322
1147013a593541
12194513682b42
13979c9b453a7
14480774a072a
152463be13c82
hex1340ee9d3e2

1323100132322 has 4 divisors (see below), whose sum is σ = 1984650198486. Its totient is φ = 661550066160.

The previous prime is 1323100132313. The next prime is 1323100132379. The reversal of 1323100132322 is 2232310013231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 789643727161 + 533456405161 = 888619^2 + 730381^2 .

It is a super-3 number, since 3×13231001323223 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330775033079 + ... + 330775033082.

Almost surely, 21323100132322 is an apocalyptic number.

1323100132322 is a deficient number, since it is larger than the sum of its proper divisors (661550066164).

1323100132322 is an equidigital number, since it uses as much as digits as its factorization.

1323100132322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 661550066163.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1323100132322 its reverse (2232310013231), we get a palindrome (3555410145553).

The spelling of 1323100132322 in words is "one trillion, three hundred twenty-three billion, one hundred million, one hundred thirty-two thousand, three hundred twenty-two".

Divisors: 1 2 661550066161 1323100132322