132310081 has 2 divisors, whose sum is σ = 132310082. Its totient is φ = 132310080.

The previous prime is 132310043. The next prime is 132310103. The reversal of 132310081 is 180013231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99820081 + 32490000 = 9991^2 + 5700^2 .

It is an emirp because it is prime and its reverse (180013231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132310081 is a prime.

It is a super-2 number, since 2×132310081² = 35011915068453122, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132310021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155040 + 66155041.

It is an arithmetic number, because the mean of its divisors is an integer number (66155041).

Almost surely, 2^132310081 is an apocalyptic number.

It is an amenable number.

132310081 is a deficient number, since it is larger than the sum of its proper divisors (1).

132310081 is an equidigital number, since it uses as much as digits as its factorization.

132310081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 132310081 is about 11502.6119207770. The cubic root of 132310081 is about 509.5627175743.

The spelling of 132310081 in words is "one hundred thirty-two million, three hundred ten thousand, eighty-one".