Base | Representation |
---|---|
bin | 11110000101010111011000… |
… | …100010010000001110110101 |
3 | 122100110201111101111020001001 |
4 | 132011113120202100032311 |
5 | 114320232041201130232 |
6 | 1145222230535003301 |
7 | 36604042426211413 |
oct | 3605273042201665 |
9 | 570421441436031 |
10 | 132310100411317 |
11 | 39181442401884 |
12 | 12a0a700b09531 |
13 | 58a9a343913aa |
14 | 2495bb33b02b3 |
15 | 1046a518296e7 |
hex | 7855d88903b5 |
132310100411317 has 2 divisors, whose sum is σ = 132310100411318. Its totient is φ = 132310100411316.
The previous prime is 132310100411287. The next prime is 132310100411339. The reversal of 132310100411317 is 713114001013231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 90763748054001 + 41546352357316 = 9527001^2 + 6445646^2 .
It is a cyclic number.
It is not a de Polignac number, because 132310100411317 - 219 = 132310099887029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132310100417317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155050205658 + 66155050205659.
It is an arithmetic number, because the mean of its divisors is an integer number (66155050205659).
Almost surely, 2132310100411317 is an apocalyptic number.
It is an amenable number.
132310100411317 is a deficient number, since it is larger than the sum of its proper divisors (1).
132310100411317 is an equidigital number, since it uses as much as digits as its factorization.
132310100411317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 132310100411317 its reverse (713114001013231), we get a palindrome (845424101424548).
The spelling of 132310100411317 in words is "one hundred thirty-two trillion, three hundred ten billion, one hundred million, four hundred eleven thousand, three hundred seventeen".
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