Base | Representation |
---|---|
bin | 10011010000001111000… |
… | …101110111001011001111 |
3 | 11200111011022221122210001 |
4 | 103100033011313023033 |
5 | 133134203344402002 |
6 | 2451454123425131 |
7 | 164406504655513 |
oct | 23201705671317 |
9 | 4614138848701 |
10 | 1323103122127 |
11 | 470141245856 |
12 | 1945146851a7 |
13 | 979ca6511c7 |
14 | 48077a3c143 |
15 | 2463c304a87 |
hex | 1340f1772cf |
1323103122127 has 2 divisors, whose sum is σ = 1323103122128. Its totient is φ = 1323103122126.
The previous prime is 1323103122041. The next prime is 1323103122167. The reversal of 1323103122127 is 7212213013231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1323103122127 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1323103122095 and 1323103122104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323103122167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661551561063 + 661551561064.
It is an arithmetic number, because the mean of its divisors is an integer number (661551561064).
Almost surely, 21323103122127 is an apocalyptic number.
1323103122127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323103122127 is an equidigital number, since it uses as much as digits as its factorization.
1323103122127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 1323103122127 its reverse (7212213013231), we get a palindrome (8535316135358).
The spelling of 1323103122127 in words is "one trillion, three hundred twenty-three billion, one hundred three million, one hundred twenty-two thousand, one hundred twenty-seven".
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