Base | Representation |
---|---|
bin | 11000101001010000… |
… | …11010011101000001 |
3 | 1021011002112111012102 |
4 | 30110220122131001 |
5 | 204044121242241 |
6 | 10024523040145 |
7 | 645606662402 |
oct | 142450323501 |
9 | 37132474172 |
10 | 13231040321 |
11 | 567a639474 |
12 | 2693070055 |
13 | 132b206655 |
14 | 8d730b9a9 |
15 | 52688d39b |
hex | 314a1a741 |
13231040321 has 2 divisors, whose sum is σ = 13231040322. Its totient is φ = 13231040320.
The previous prime is 13231040293. The next prime is 13231040323. The reversal of 13231040321 is 12304013231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12777137296 + 453903025 = 113036^2 + 21305^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13231040321 is a prime.
Together with 13231040323, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13231040293 and 13231040302.
It is not a weakly prime, because it can be changed into another prime (13231040323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615520160 + 6615520161.
It is an arithmetic number, because the mean of its divisors is an integer number (6615520161).
Almost surely, 213231040321 is an apocalyptic number.
It is an amenable number.
13231040321 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231040321 is an equidigital number, since it uses as much as digits as its factorization.
13231040321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13231040321 its reverse (12304013231), we get a palindrome (25535053552).
The spelling of 13231040321 in words is "thirteen billion, two hundred thirty-one million, forty thousand, three hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •