Base | Representation |
---|---|
bin | 11110000101011000010000… |
… | …001100000001000001111011 |
3 | 122100110210220110101211022211 |
4 | 132011120100030001001323 |
5 | 114320240444212342404 |
6 | 1145222503331155551 |
7 | 36604104524404321 |
oct | 3605302014010173 |
9 | 570423813354284 |
10 | 132311034105979 |
11 | 39181881458463 |
12 | 12a0a921745bb7 |
13 | 58a9b52954641 |
14 | 2495c613bbd11 |
15 | 1046aa87aeb04 |
hex | 78561030107b |
132311034105979 has 2 divisors, whose sum is σ = 132311034105980. Its totient is φ = 132311034105978.
The previous prime is 132311034105977. The next prime is 132311034106081. The reversal of 132311034105979 is 979501430113231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132311034105979 - 21 = 132311034105977 is a prime.
Together with 132311034105977, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (132311034105977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155517052989 + 66155517052990.
It is an arithmetic number, because the mean of its divisors is an integer number (66155517052990).
Almost surely, 2132311034105979 is an apocalyptic number.
132311034105979 is a deficient number, since it is larger than the sum of its proper divisors (1).
132311034105979 is an equidigital number, since it uses as much as digits as its factorization.
132311034105979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 612360, while the sum is 49.
The spelling of 132311034105979 in words is "one hundred thirty-two trillion, three hundred eleven billion, thirty-four million, one hundred five thousand, nine hundred seventy-nine".
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