Base | Representation |
---|---|
bin | 1100000010001001101110… |
… | …1011011101010001000111 |
3 | 1201211212210212212111000121 |
4 | 3000202123223131101013 |
5 | 3213234303422212411 |
6 | 44050142154122411 |
7 | 2533626160663666 |
oct | 300423353352107 |
9 | 51755725774017 |
10 | 13231111132231 |
11 | 4241312333023 |
12 | 1598340420407 |
13 | 74c8c461a375 |
14 | 33a563d4addd |
15 | 17e289069571 |
hex | c089badd447 |
13231111132231 has 2 divisors, whose sum is σ = 13231111132232. Its totient is φ = 13231111132230.
The previous prime is 13231111132207. The next prime is 13231111132241. The reversal of 13231111132231 is 13223111113231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13231111132231 - 223 = 13231102743623 is a prime.
It is a super-2 number, since 2×132311111322312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13231111132196 and 13231111132205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13231111132201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615555566115 + 6615555566116.
It is an arithmetic number, because the mean of its divisors is an integer number (6615555566116).
Almost surely, 213231111132231 is an apocalyptic number.
13231111132231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231111132231 is an equidigital number, since it uses as much as digits as its factorization.
13231111132231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 648, while the sum is 25.
Adding to 13231111132231 its reverse (13223111113231), we get a palindrome (26454222245462).
The spelling of 13231111132231 in words is "thirteen trillion, two hundred thirty-one billion, one hundred eleven million, one hundred thirty-two thousand, two hundred thirty-one".
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